Question

2x +3y=28 and 3x-2y=3 solve x=?,y=?​

Answer 1

2x+3y=28

3x-2y=3

Now, by solving 2 equations simultaneously,

2x+3y=28 - - - - - - (*3) (multiplying by 3)

3x-2y=3 - - - - - - - - -(*2) (multiplying by 2)

Two equations will become,

6x+9y=84

6x -4y= 6 (subtracting 2nd equation)

(-) (+) (-)

13y=78

y=78 [y=6]

13

Now substituting y=6 in any one of the equations,

3x-2y=3

3x-2(6)=3

3x-12=3

3x=15

x=15 [x=5]

3