Question

(-2x+3y+2z)^2 expand this

Answer 1

by (a+b+c) ^2=a^2+b^2+c^2+2ab+2bc+2ac
(-2x+3y+2z) ^2=(-2x) ^2+(3y) ^2+(2z) ^2+2(-2x) (3y) +2(3y) (2z) +2(-2x) (2z)
=4x^2+9y^2+4z-12xy+12yz-8xz
hope it helps you

Answer 2

Answer:

Step-by-step explanation:

given :- ( 2x + 3y + 2z )²

by using identity ( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ac

here a = 2x, b = 3y and c = 2z

( 2x + 3y + 2z )² = (2x)² + (3y)² + (2z)² + 2(2x)(3y) + 2(3y)(2z) + 2(2x)(2z)

= 4x² + 9y² + 4z² + 12xy + 12yz + 12xz