Question

2x-3y/3=3+3y-4x/4,

1/3(6y+7x)=1/5(7x+12y)+4

Answer 1

Answer:

Answer:(x,y)= (51/5,69/5)

Answer:(x,y)= (51/5,69/5)Step-by-step explanation:

Answer:(x,y)= (51/5,69/5)Step-by-step explanation:solution :

Answer:(x,y)= (51/5,69/5)Step-by-step explanation:solution :2x+3(y/3) =3+3y-4(x/4) -----→ 1

+3y-4(x/4) -----→ 11/3(6y+7x) = 1/5(7x+12y)+4 -----→2

+3y-4(x/4) -----→ 11/3(6y+7x) = 1/5(7x+12y)+4 -----→2-----→ 1

Cancelled by 3,4

2x+y=3+3y-x

2x+x+y-3y=3

3x-2y=3 -----→ 3

-----→ 2

Multiple with 3 both side

6y+7x = 3/5(7x+12y)+12

6y+7x =21/5x+36/5y+12

Multiple with 5 both side

30y+35x =21x+36y+60

30y-36y=21x-35x+60

-6y=-14x+60

Divided by -6 both side

y=7/3x-10 -----→ 4

substitute the value of y in (eq) -----→ 3

3x-2(7/3x-10) =3 -----→ 5

Multiple with -2 (7/3x-10)

3x-14/3x+20 =3

Multiple both side of the (eq) by 3

9x-14x+60=9

-5x+60=9

-5x=9-60

-5x=-51

Divided by -5 both side

x=51/5 -----→ 6

substitute the value of x in eq -----→ 4

y=7/3x-10

y=(7/3) (51/5) -10

y=7 (17/5) -10

y=119/5 -10

y=119-50/5

y=69/5 -----→ 7

(x,y)= (51/5,69/5)