(2x-3y)³+(3y-5z)³+(5z-2x)³
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Step-by-step explanation:
Let 2x-3y be x
Let 3y-5z be y
Let 5z-2x be z
x+y+z=0
Therefore, x^3+y^3+z^3=3xyz
(2x-3y)^3+(3y-5z)^3+(5z-2x)^3= 3*2x*3y*5z=90xyz
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