2x-3y=3,4x-y=5 by substitution mathod?
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Answer:
from eqution 2
y=4x-5 substituting in eq.1
2x-3(4x-5)=3
2x-12x+15=3
-10x=-12
10x =12
x=6/5
x=6/5 putting in eq .1
2*6/5-3y=3
12/5-3=3y
12-15/5=3y
-3/5=3y
y=-1/5
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