Question

(2x-3y)^³+(4z-2x)^³+(3y-4z)^³ factorize

Answer 1

Answer:

-36x^2y+54x^2y-96xz^2+48x^2z-64z^3-

108y^2z+144yz^2

Step-by-step explanation:

By using identity (x-y)^3=x^3-y^3-3x^2y+3xy^2

(2x-3y)^3+(4z-2x)^3+(3y_4z)^3

=8x^3-27y^3-36x^2y+54xy^2+64z^3-8x^3-

96xz^2+48x^2z+27y^3-64z^3-108y^2z+

144yz^2

-36x^2y+54x^2y-96xz^2+48x^2z-64z^3-

108y^2z+144yz^2