2x + 3y = 32. 11y - 9x = 23. solve this equation
Answers
Answered by
3
here we use elimination method ,
2x + 3y = 32 ----------(1)
2x = 32 - 3y
x = ( 32- 3y)/2
now put x = ( 32 - 3y)/2 in equation (2)
e.g 11y - 9( 32 -3y)/2 = 23
22y - 288 + 27y = 46
49y = 288 +46 = 334
y = 334/49
put y = 334/49 in x = ( 32 - 3y)/2
x = ( 32 - 3× 334/49)/2
= ( 32 - 1002/49)/2
= ( 1568 -1002)/98
= ( 566)/98
hence, x = 334/49 and y = 566/98
2x + 3y = 32 ----------(1)
2x = 32 - 3y
x = ( 32- 3y)/2
now put x = ( 32 - 3y)/2 in equation (2)
e.g 11y - 9( 32 -3y)/2 = 23
22y - 288 + 27y = 46
49y = 288 +46 = 334
y = 334/49
put y = 334/49 in x = ( 32 - 3y)/2
x = ( 32 - 3× 334/49)/2
= ( 32 - 1002/49)/2
= ( 1568 -1002)/98
= ( 566)/98
hence, x = 334/49 and y = 566/98
Anonymous:
Thank-you
Answered by
5
hey dear ,
=) 2x + 3y = 32 -----------(1)
=) 11y - 9x = 23 ---------(2)
multiplying eqn (1) by 9 and eqn (2) by 2 and add them.
18x + 27y = 288
22y - 18x = 46
+
__________________
=). 49y + 0 = 334
=). y = 334/49 =6.81
put value of y in equation (1)
=) 2x + 3(6.81) =32
=) 2x = 32 - 20.43
=) 2x = 11.57
=) x = 11.57/2 =5.78
so value of x = 5.78
==) y = 6.81
________________-–_____________
hope it will help u
=) 2x + 3y = 32 -----------(1)
=) 11y - 9x = 23 ---------(2)
multiplying eqn (1) by 9 and eqn (2) by 2 and add them.
18x + 27y = 288
22y - 18x = 46
+
__________________
=). 49y + 0 = 334
=). y = 334/49 =6.81
put value of y in equation (1)
=) 2x + 3(6.81) =32
=) 2x = 32 - 20.43
=) 2x = 11.57
=) x = 11.57/2 =5.78
so value of x = 5.78
==) y = 6.81
________________-–_____________
hope it will help u
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