Question

(2x+3y)(3x+2y)soltuion

Answer 1

Simplifying

(2x + -3y)(3x + 2y) = 0

Multiply (2x + -3y) * (3x + 2y)

(2x * (3x + 2y) + -3y * (3x + 2y)) = 0

((3x * 2x + 2y * 2x) + -3y * (3x + 2y)) = 0

Reorder the terms:

((4xy + 6x2) + -3y * (3x + 2y)) = 0

((4xy + 6x2) + -3y * (3x + 2y)) = 0

(4xy + 6x2 + (3x * -3y + 2y * -3y)) = 0

(4xy + 6x2 + (-9xy + -6y2)) = 0

Reorder the terms:

(4xy + -9xy + 6x2 + -6y2) = 0

Combine like terms: 4xy + -9xy = -5xy

(-5xy + 6x2 + -6y2) = 0

Solving

-5xy + 6x2 + -6y2 = 0

Solving for variable 'x'.

Factor a trinomial.

(2x + -3y)(3x + 2y) = 0

Answer 2

(2x+3y)(3x+2y)

=> 2x(3x+2y) +3y(3x+2y)

=> 6x²+4xy+9xy+6y²

=> 6x²+6y²+13xy

$hope \: it \: helps$