Question

2x-3y-4=0 and 3x+2y=19 by elimination method
pls help me ASAP

Answer 1

hope this may help you dear

Answer 2

$\large\underline{\sf{Solution-}}$

Given pair of linear equation is

$\rm :\longmapsto\:2x - 3y - 4 = 0$

and

$\rm :\longmapsto\:3x + 2y = 19$

can be rewritten as

$\rm :\longmapsto\:2x - 3y = 4 - - - (1)$

and

$\rm :\longmapsto\:3x + 2y = 19 - - - - (2)$

Multiply equation (1) by 2, we get

$\rm :\longmapsto\:4x - 6y = 8 - - - (3)$

Now, multiply equation (2) by 3, we get

$\rm :\longmapsto\:9x + 6y = 57 - - - (4)$

On adding equation (3) and (4), we get

$\rm :\longmapsto\:13x = 65$

$\bf\implies \:x = 5 - - - (5)$

On substituting value of x in equation (1) we get

$\rm :\longmapsto\:2(5) - 3y = 4$

$\rm :\longmapsto\:10 - 3y = 4$

$\rm :\longmapsto\: - 3y = 4 - 10$

$\rm :\longmapsto\: - 3y = - 6$

$\bf\implies \:y = 2$

Hence,

$\begin{gathered}\begin{gathered}\bf\: \rm :\longmapsto\:Solution \: is \: -\begin{cases} &\bf{x = 5} \\ &\bf{y = 2} \end{cases}\end{gathered}\end{gathered}$

Verification :-

Consider equation (2)

$\rm :\longmapsto\:3x + 2y = 19$

On substituting the values of x and y, we get

$\rm :\longmapsto\:3(5) + 2(2) = 19$

$\rm :\longmapsto\:15 + 4 = 19$

$\rm :\longmapsto\:19 = 19$

Hence, Verified