2x+3y+4= 0; x- 5y - 11
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Answer:
2x+3y=-4 (eq1)
x-5y=11. (eq2)
Multiply eq2 by 2
2x-10y=22 (eq3)
2x-10y=22
2x+3y=-4
_________
13y=26
y=2
Put Y=2 in eq1
2x+3(2)=-4
2x+6=-4
2x=-4-6
2x=10
x=5
(x,y)=(5,2)
I hope this will help you out
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