2x+3y+4=0,x-5y=11 solve by elimination method
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2x+3y+4=0
x-5y=11
multipy 2nd equation with 2 then you get
2x-10y=22
now subtract this equation from equation 1
2x+3y+4=0
2x-10y. =22
by solving we get
y=-2
and substitute y value in above equation and get
x=1
x-5y=11
multipy 2nd equation with 2 then you get
2x-10y=22
now subtract this equation from equation 1
2x+3y+4=0
2x-10y. =22
by solving we get
y=-2
and substitute y value in above equation and get
x=1
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