Question

2x+3y+4=0;x-5y=11 what is the value of x&y

Answer 1

2x+3y+4=0 -----------------------(1)
x-5y=11 ---------------------(2)

In equation (2)
$x - 5y= 11$
$x = 11 + 5y$
Let this be Result 1

Now putting Result 1 in Equation 1

2x+3y+4=0
2(11+5y)+3y+4=0
22 + 10y + 3y + 4 =0
22 + 13y + 4 = 0
13y + 26 = 0
13y = -26
y = -26/13
y = -2

Now, Putting value of y in equation2

x - 5y = 11
x -5(-2) = 11
x + 10 = 11
x = -1

Answer:- x = -1 and y = -2

Answer 2

Answer:

=> The value of x is $1$ and y is $-2.$

Step-by-step explanation:

Given that:-

$x-5y=11$

$x=11+5y$           $...(1)$

$2x+3y+4=0$     $...(2)$

Now, substitute value of $x$ from $(1)$ in the above equation,

So will we get,

=> $2(11+5y)+3y=-4$

By further simplifying it, we get

=> $22+10y+3y=-4$

=> $10y+3y=-4-22$

Combining the terms, we get

=> $13y=-26$

Divide both the sides by $13$, we get

=> y = -2

So, the value of y is -2.

Putting the value of y in $(1)$, we get

=> $x=11+5y$

=> $x=11+5\times (-2)$

=> $x=11-10$

=> $x=1$

So, the value of x is 1.