Question

(2x-3y+4)² using identity

Answer 1

using identity => (a + b + c)² = a² + b² + c² + 2(ab + bc + ca)

(2x + 3y - 4z)²

=> (2x)² + (3y)² + ( - 4z)² + 2[ (2x).(3y) + (3y).(- 4z) + (- 4z).(2x)]

=> 4x² + 9y² + 16z² + 2(6xy - 12yz - 8zx)

=> 4x² + 9y² + 16z² + 12xy - 24yz - 16zx

Answer 2

Answer:

$(2x + 3y + 4)^2$