Math, asked by boraaagam, 9 months ago

2x+3y=-4 ; x-5y=11 solve simultaneous equation​

Answers

Answered by kanojiaparas582
10

Step-by-step explanation:

2x+3y+4=0 -----------------------(1)

x-5y=11 ---------------------(2)

In equation (2)

x - 5y= 11x−5y=11

x = 11 + 5yx=11+5y

Let this be Result 1

Now putting Result 1 in Equation 1

2x+3y+4=0

2(11+5y)+3y+4=0

22 + 10y + 3y + 4 =0

22 + 13y + 4 = 0

13y + 26 = 0

13y = -26

y = -26/13

y = -2

Now, Putting value of y in equation 2

x - 5y = 11

x -5(-2) = 11

x + 10 = 11

x = -1

Answer:- x = -1 and y = -2

Answered by yaduvanshitab
11

Answer:

2x+3y=-4.---------1 equation

x-5y. =11. ----------2 equation

2x+3y= -4

2x-10y=22

by subtracting both the equation we will get....

13y= -26

y=-2

putting the value of y in eq 1

2x+3 x (-2)= -4

2x-6=-4

2x=2

x=1

hope this helps you.

pls mark as brainliest.

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