Math, asked by kashish143ilu143, 4 months ago

2x+3y=40 and 3x+2y=35 by cross multiplecation
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Answers

Answered by REDPLANET
16

\underline{\boxed{\bold{ \bigstar \; Question \; \bigstar }}}  

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➠ Solve : 2x + 3y = 40 and 3x + 2y = 35 by cross multiplication

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\underline{\boxed{\bold{ \bigstar \; Important \; Information \; \bigstar }}}  

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❏ Cross multiplication method is one of the effective method in solving a pair of linear equation in 2 variables.

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❏ If 2 equations are as follow :

  • a₁x + b₁y + c₁ = 0
  • a₂x + b₂y + c₂ = 0

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then,

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\star \; \; \; \;  \; \;\; \; \; \; \; \;  \boxed { \orange { :\longmapsto x = \dfrac{b_1c_2 - b_2c_1}{a_1b_2 - a_2b_1} } }

\star \; \;  \; \;  \; \;  \; \;  \; \;  \; \; \boxed { \orange { :\longmapsto y = \dfrac{c_1a_2 - c_2a_1}{a_1b_2 - a_2b_1} } }

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\underline{\boxed{\bold{ \bigstar \; Given \; \bigstar }}}  

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➠ Equation 1 : 2x + 3y - 40 = 0

➠ Equation 2 : 3x + 2y - 35 = 0

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\underline{\boxed{\bold{ \bigstar \; Answer \; \bigstar }}}  

Let's Start !

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Here,

❖ Equation 1 : 2x + 3y - 40 = 0

  • a₁ = 2                  
  • b₁ = 3
  • c₁ = (-40)

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❖ Equation 2 : 3x + 2y - 35 = 0

  • a₂ = 3
  • b₂ = 2
  • c₂ = (-35)

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  • Calculation for variable "x"

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\boxed { \bold { :\longmapsto x = \dfrac{b_1c_2 - b_2c_1}{a_1b_2 - a_2b_1} } }

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:\implies x = \dfrac{\{(3)(-35)\} - \{(2)(-40)\}}{(2)(2) - (3)(3)}

:\implies x = \dfrac{-105 - (-80)}{4- 9}

:\implies x = \dfrac{-105 + 80}{-5}

:\implies x = \dfrac{-25}{-5}

\bold {\blue { :\implies x = 5 }}

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  • Calculation for variable "y"

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\boxed { \bold { :\longmapsto y = \dfrac{c_1a_2 - c_2a_1}{a_1b_2 - a_2b_1} } }

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:\implies y = \dfrac{\{(-40)(3)\} - \{(-35)(2)\}}{(2)(2)-(3)(3)}

:\implies y = \dfrac{(-120)- (-70) }{4-9}

:\implies y = \dfrac{-120 +70 }{-5}

:\implies y = \dfrac{-50 }{-5}

\bold{ \blue { :\implies y = 10} }

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\boxed{\boxed{\bold{\therefore Value\;of\;x = 5 }}}

\boxed{\boxed{\bold{\therefore Value\;of\;y = 10 }}}

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Hope this helps u.../

【Brainly Advisor】


REDPLANET: Welcome :D
Answered by mishra6753
2

Answer:

value of x =5

value of y = 10

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