Question

2x+3y=46 and 3x+5y=74 by substitution method

Answer 1

$\bf{\blue{\bigstar}}$ AnsweR :

2x + 3y = 46 ... (1)

⇒ 2x = 46 - 3y

⇒ x = (46-3y) / 2 ... (2)

Now 3x + 5y = 74 ... (3)

Now sub. eq(2) in eq(3) , we get ,

⇒ 3 (46-3y)/2 + 5y = 74

⇒ 138 - 9y + 10y = 148

⇒ $\bold{\bf{\blue{y = 10}}}$

Now sub. y value in eq(1) , we get ,

⇒ 2x = 46 - 3(10)

⇒ 2x = 16

⇒ $\bold{\bf{\blue{x = 8}}}$

Answer 2

Answer:

Step-by-step explanation:

2x+3y=46 --1

3x+5y=74 --2
1=> 2x= 46-3y

       x= 46-3y/2 --3
substitute x=46-3y/2 in equation 2:

= 3(46-3y/2) + 5y = 74

= 138-9y+10y=148

Y=10 (skipped 2 steps till value)

substitute value of y in 1:

2x+30=46

= 2x= 16

x=8.

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