Question

(2x-3y +4z)^2 factorise​

Answer 1

Answer:

→ 4x² + 9y² + 16z² - 12xy - 24yz + 16zx .

Step-by-step explanation:

Identity to be used :-

→ ( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ca .

We have,

→ ( 2x - 3y + 4z )².

= [ ( 2x ) + ( -3y ) + ( 4z ) ]² .

Here, a = 2x , b = -3y and c = 4z .

( 2x )² + ( -3y )² + ( 4z )² + 2(2x)(-3y) + 2(-3y)(4z) + 2(4z)(2x) .

= 4x² + 9y² + 16z² - 12xy - 24yz + 16zx .

Hope it helps

Answer 2

Answer:

4x^2+ 9y^2+16z^2+2(-6xy-12yz+8xz)