Question

(-2x-3y+4z)^2 in standard form​

Answer 1

Answer:

you have to use identity here,

Step-by-step explanation:

Formula: (a-b-c)^2= a^2+b^2+c^2- 2ab-2ac+2bc

,,, Given values, a= 2×b = -3yc= - 4z

subsitute the given values in the identit

(2x) ^2+(-3y) ^2+(-4z^2) - (2x) (-3y) -2((2x) (-4z)) + 2((-3y(-4z)) = 4x^2+ 9y^2+ 16z^2+ 12xy+16xz+24yz