Question

(2x+3y+4z)2
$(2x + 3y + 4z) {}^{2}$

Answer 1

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Here is u r Ans ➡


✨
$(2x + 3y + 4z) {}^{2}$

$= (2x) {}^{2} + ( 3y) {}^{2} + (4z) {}^{2} + 2 \times 2x \times 3y \times + 2 \times 2x \times 4z + 2 \times 3y \times 4z$

$= 4x {}^{2} + 9y {}^{2} + 16z {}^{2} + 12xy + 16xz + 24yz$

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Answer 2

As this question,

=> (a+b+c)^2= a^2+b^2+c^2+2(ab+bc+ca)

=> (2x+3y+4z)^2 = (2x)^2+(3y)^2+(4z)^2+2(2x*3y+3y*4z+4z*2x)

=> 4x^2+9y^2+16z^2+2(6xy+12yz+8zx)

=> 4x^2+9y^2+16z^2+12xy+24yz+16zx

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