(2x+3y+4z)(4x^2+9y^2+16z^2-6xy-12yz-8zx
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Solution :-
⍟︎ (2x + 3y + 4z) (4x² + 9y² + 16z² - 6xy - 12yz - 8zx)
➙ (2x + 3y + 4z) {(2x)² + (3y)² + (4z)² - (2x) × (3y) - (3y) × (4z) - (4z) × (2x)}
➙ (2x)³ + (3y)³ + (4z)³ - 3 × (2x) × (3y) × (4z)
➙ 8x³ + 27y³ + 64z³ - 72xyz
∴ The answer of this question is 8x³ + 27y³ + 64z³ - 72xyz
Formula used :-
❂ (a + b + c) (a² + b² + c² - ab - bc - ca)
➙ a³ + b³ + c³ - 3abc
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