Math, asked by Anonymous, 11 months ago

(2x+3y+4z) ( 4x^2 + 9y^2 + 16z^2 - 6xy - 12yz - 8zx )


pls solve fast
if you give the correct answer i will mark as the brainliest.
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Answers

Answered by harshhero77
32

Step-by-step explanation:

(2x + 3y+ 4z) {(2x)^2 + (3y)^2 + (4z)^2 - (2x)(3y) - ( 3y)(4z) - ( 4z)(2x)}

: . it is in the form ( x^3 + y^3 + z^3)- 3xyz

: . the answer is ( 2x^3 + 3y^3+ 4z^3) - 3( 2x + 3y + 4z )

Answered by magarasri6
7

Answer:

this may help you buddy

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