(2x+3y+4z) ( 4x^2 + 9y^2 + 16z^2 - 6xy - 12yz - 8zx )
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Answered by
32
Step-by-step explanation:
(2x + 3y+ 4z) {(2x)^2 + (3y)^2 + (4z)^2 - (2x)(3y) - ( 3y)(4z) - ( 4z)(2x)}
: . it is in the form ( x^3 + y^3 + z^3)- 3xyz
: . the answer is ( 2x^3 + 3y^3+ 4z^3) - 3( 2x + 3y + 4z )
Answered by
7
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