2x=3y=4z हो तो x+y+z का मान क्या है
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x+y+z=2+3+4 hope it help you
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Since 2x = 3y = 4z, we see that:
k = 2x, k = 3y, and k = 4z, for some k.
Solving these for x, y, and z yields:
x = k/2, y = k/3, and z = k/4.
Therefore:
x+y+z = (k/2)+(k/3)+(k/4)
= 6k+4k+3k, by multiplying all parts by 12
= 6+4+3, by dividing all parts by k.
∴x+y+z = 6+4+3
I hope this helps!
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