2x=3y=4z the value of x:y:z
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Answered by
5
Hey
Here is your answer !!
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❇ Let 2x = 3y = 4z = k ( where k is constant )
Then
❇x = k/2
❇y = k/3
❇z= k/4
✴Now ;
k/2 : k/3 :k/4
❇LCM of 2 ,3 , 4 = 24
❇Substitute the value of k as 1
1/2 : 1/3 : 1/4
❇Multiply each term by 24
❇1/2×24 : 1/3×24 : 1/4÷24
❇12 : 8 : 6
❇6 : 4 : 3
Hence x : y : z = 6 : 4 : 3 ✔
__________________
Hope this will help you !☺☺
@Ujjawal
Here is your answer !!
_________________
❇ Let 2x = 3y = 4z = k ( where k is constant )
Then
❇x = k/2
❇y = k/3
❇z= k/4
✴Now ;
k/2 : k/3 :k/4
❇LCM of 2 ,3 , 4 = 24
❇Substitute the value of k as 1
1/2 : 1/3 : 1/4
❇Multiply each term by 24
❇1/2×24 : 1/3×24 : 1/4÷24
❇12 : 8 : 6
❇6 : 4 : 3
Hence x : y : z = 6 : 4 : 3 ✔
__________________
Hope this will help you !☺☺
@Ujjawal
Answered by
12
Heyyyyyyyy!!!!!
Answer Of Your Question☺️
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Question:-
2x=3y=4z
so, we see that,
k=2x, k=3y, k=4z [For Some k]
now,
x=k/2, y=k/3, z=k/4
therefore,
x:y:z
= (k/2):(k/3):(k/4)
=6k:4k:3k [by multiplying all parts of the proportion by 12]
=6:4:3 [ Dividing all parts by k ]
so, x:y:z=6:4:3
------------------------------------------------
Hope My Answer Helped You✌️✌️
___________________________
Answer Of Your Question☺️
-----------------------------------------
Question:-
2x=3y=4z
so, we see that,
k=2x, k=3y, k=4z [For Some k]
now,
x=k/2, y=k/3, z=k/4
therefore,
x:y:z
= (k/2):(k/3):(k/4)
=6k:4k:3k [by multiplying all parts of the proportion by 12]
=6:4:3 [ Dividing all parts by k ]
so, x:y:z=6:4:3
------------------------------------------------
Hope My Answer Helped You✌️✌️
___________________________
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