Math, asked by dubeymp45730, 10 months ago

2x+3y-5=0 3x-2y-14=0 by elimination method

Answers

Answered by praneethppk123
2

Answer:

2x+3y=5....eq1

3x-2y=14.....eq2

2(eq1)+3(eq2)

2x+6y=10

9x-6y=42

11x=5x=52/11

3y+104/11=5

3y=-49/11

Answered by pyarip
3

Answer:

2x+3y=5

3x-2y=14

Multiply 1 st equation by 3

Multiply 2nd equation by 2

6x+9y=15

6x-4y=28

on subtracting we get

11y=-13

y=-13/11

2x-39/11=5

=2x=5+39/11

=2x=94/11

=x=47/11

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