2X+3Y-5=0 6X+Ky+15=0 find k
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2x + 3y -5 =0 ----------1 equation
6x +Ky +15 =0 ----------2 equation
when we do common from 2 nd equation
3 (2x +ky +5) ----------3 equation
so,, by this we can say that in the place of k = 3... so,, from comparing 2nd equation and 3rd equation .. we get k = 9
so the answers is k = 9
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