Question

2x – 3y = 5; 3x + 4y = – 1 by substitution method

Answer 1

$\huge\bold\pink{AnswEr:-}$

${\underline{\underline{\sf{\red{Given:-}}}}}$

2x- 3y =5 (1)

3x + 4y = -1 (2)

† ${\underline{\underline{\sf{\blue{Using \ substitution \ method:-}}}}}$

★ $\red{Taking \ eq. (1) →}$

2x - 3y = 5

2x = 5 - 3y

x = $\dfrac{5 - 3y}{2}$ (3)

★ Putting eq. (3) in eq. (2) →

$3( \dfrac{5-3y}{2}) + 4y = -1$

$\dfrac{15-9y}{2} + 4y = -1$

$\dfrac{15 - 9y + 8y}{2} = -1$

15 - 9y + 8y = -2

-9y + 8y = -2 - 15

- y = -17

★ y = 17

★ $\red{Putting \ value \ of \ y \ in \ eq. (3) →}$

x = $\dfrac{5 - 3×17}{2}$

x = $\dfrac{5 - 51}{2}$

x = $\frac{-46}{2}$

★ x = -23

† ${\underline{\underline{\sf{\pink{Hence, \ x = -23 \ and \ y = 17.}}}}}$

_______________________________________