Question

2x+3y=5;3x-5y=5. Solve the simultaneous equation

Answer 1

${\huge{\tt{\underline{\underline{\color{orange}{Answer :-}}}}}}$

$2x + 3y = 5---(1)\\ 3x - 5y = 5---(2)$

$multiply \: (1) \: by \: 5 \: and \: (2) \: by \: 3$

$10x + 15y = 25 - - - (3) \\ \: \: 9x - 15y = 15 - - - (4)$

$add \: (3) \: and \: (4)$

$19x = 40$

${\underline{\bold{x = \frac{40}{19} }}}$

$put \: x = \frac{40}{19} \: in \: (1)$

$2( \frac{40}{19} ) + 3y = 5$

$\frac{80}{19} + 3y = - 5$

$3y = - 5 - \frac{80}{19}$

$3y = \frac{95 - 80}{19}$

$3y = \frac{5}{19}$

$y = \frac{5}{3 \times 19}$

${\underline{\bold{y = \frac{5}{57} }}}$

$\underbrace\red{hope \: it \: helps \: u \: mate}$