2x+3y=5. 3x-y=2 by elimination method
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Answer:
x=1,y=1
Step-by-step explanation:
(2x+3y=5)×3
=6x+9y=15 (1st eq)
(3x-y=2)×2
=6x-2y=4 (2nd eq)
2nd eq -1st eq
6x-2y=4
6x+9y=15
(-) (-)
-11y=-11
y=1
subtitute'y' in 1st eq
6x+9(1)=15
6x+9=15
6x=6
x=1
I hope this answer may help you
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