2x-3y=5,3x-y=2. Solve by elimination
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Answer:
2x + 3y = 5
So 6x + 9y = 15 (equation 1)
3x + y = 4
6x + 2y = 8 (equation 2)
(6x + 9y) - (6x + 2y) = 15 - 8
7y = 7
y = 1 (equation 3)
Substitute y = 1 into equation 2,
3x + (1) = 4
x = 1
(x, y) = (1, 1)
Substitution
2x + 3y = 5 (equation 1)
3x + y = 4, so y = 4 - 3x (equation 2)
Substitute equation 2 into equation 1,
2x + 3(4 - 3x) = 5
2x + 12 - 9x = 5
12 - 7x = 5
12 - 5 = 7x
7x = 7
x = 1 (Equation 3)
Substitute equation 3 into equation 2,
y = 4 - 3(1) = 1
(x, y) = (1, 1)
Graphical method
Find the x and y intercept of each line, draw the lines on the same set of cartesian coordinates, and look at where the lines cross.
(x, y) = (1, 1)
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