Question

2x+3y=5 and 3x+4y=7 by elimination method ​

Answer 1

Given:

2x+3y=5 and 3x+4y=7

solve it by using elimination method

First name is as equation (1) and equation (2)

3 × [2x+3y=5  ]   -(1)

2 × [3x+4y=7   ]   -(2)

Multiply equation 1 by 3 and equation 2 by 2 for the coefficients of one variable.

6x + 9y = 15   -(3)

-6x + 8y = 14   -(4)

y= 1

Put value of y in equation (1) we get

2x + 3y = 5

2x + 3(1) = 5

2x + 3 = 5

2x = 5 - 3

2x = 2

x = 2/2

x= 1

Hence the value of x and y is 1

Answer 2

Given that:-

$2x+3y=5...(i)$

$3x+4y=7...(ii)$

Now, multiplying equation (i) by 3 and (ii) by 2, we get

$=>2x+3y=5\times3\\=>6x+9y-15=0...(iii)$

$=>3x+4y=7\times 2\\=>6x+8y-14=0...(iv)$

For the value of y we have to subtract equations (iii) and (iv), we get

$=>-y+1=0\\=>y=1$

By putting the value of y in equation (i), we get

$=>2x+3(1)=5\\=>2x+3=5\\=>2x=5-3\\=>2x=2\\=>x=\frac{2}{2}\\=>x=1$

Hence, the value for x is 1 and y is 1