Question

2x – 3y = 5 and 4x - y = 15, so the equations are​

Answer 1

Answer:-

In line 2x - 3y = 5 , value of x = 0 then y = \frac{-5}{3}

3

−5

and y = 0 then x = \frac{5}{2}

2

5

.

In line 4x - 6y = 15, value of x = 0 then y = \frac{5}{-2}

−2

5

and y = 0 then x = \frac{15}{4}

4

15

Step-by-step explanation:

In this question

We have given that

2x - 3y = 5

4x - 6y = 15

So, 2x - 3y - 5 = 0

4x - 6y - 15 = 0

Then, a_1 = 2, b_1 = -3, c_1 = -5

b_1 = 4, b_2 = -6, c_2 = -15

\frac{a_1}{a_2}

a

2

a

1

= \frac{2}{4}

4

2

\frac{a_1}{a_2}

a

2

a

1

= \frac{1}{2}

2

1

\frac{b_1}{b_2}

b

2

b

1

= \frac{-3}{-6}

−6

−3

\frac{b_1}{b_2}

b

2

b

1

= \frac{1}{2}

2

1

\frac{c_1}{c_2}

c

2

c

1

= \frac{-5}{-15}

−15

−5

\frac{c_1}{c_2}

c

2

c

1

= \frac{1}{3}

3

1

Therefore, \frac{a_1}{a_2}

a

2

a

1

≠ \frac{b_1}{b_2}

b

2

b

1

≠ \frac{c_1}{c_2}

c

2

c

1

So, equation are inconsistent

Then, 2x + 3y -5 = 0

Putting x = 0, Putting y = o,

0 - 3y - 5 = 0 2x - 5 = 0

y = \frac{-5}{3}

3

−5

x = \frac{5}{2}

2

5

Similarly, 4x - 6y - 15 = 0

Putting x = 0, Putting y = o,

0 - 6y - 15 = 0 4x - 15 = 0

y = \frac{15}{-6}

−6

15

x = \frac{15}{4}

4

15

y = \frac{5}{-2}

−2

5

Therefore , In line 2x - 3y = 5 , value of x = 0 then y = \frac{-5}{3}

3

−5

and y = 0 then x = \frac{5}{2}

2

5

.

In line 4x - 6y = 15, value of x = 0 then y = \frac{5}{-2}

−2

5

and y = 0 then x = \frac{15}{4}

4

15