Math, asked by monikaphad25, 1 year ago

2x+3y-5;y-32=2;2+3x=4 solve

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Answered by singhabhimanyupbxvvz

1

2x+3y-5,y-32=2,3+3x=4 .y-32=2 y=3+32=35.3+3x=4 x=4-3÷3=1÷3.2y+3y-5=2×35+3×1÷3-5. 70+1-5=71-5=66

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