Question

2x-3y+6= ; 2x+3y-18=0 Solve by substituting method

Answer 1

Answer:

$\huge\bigstar\huge\tt\underline\red{ᴀɴsᴡᴇʀ }\bigstar$

$2x - 3y + 6 = 0$

$x = \frac{ - 6 + 3y}{2}$

now put the value of x in next equation:-

$2x + 3y - 18 = 0$

$2 (\frac{ - 6 + 3y}{2} ) + 3y - 18 = 0$

$\frac{ - 12 + 6y + 6y - 36}{2} = 0$

$- 12 + 12y = 36$

$12y = 48$

$y = 4$

now put value of y in above equation:-

$x = \frac{ - 6 + 3y}{2} = \frac{ - 6 + 3 \times 4}{2} = \frac{6}{2} = 3$

hence,X=3 & Y=4