Question

-2x+3y=6 and4x-ky=8... find unique solution of k value

Answer 1

$a_1=-2,a_2=4,b_1=3,b_2=-k\\ \frac{a_1}{a_2} = \frac{b_1}{b_2}≠ \frac{c_1}{c_2} \\\frac{a_1}{a_2} = \frac{b_1}{b_2}\\ \frac{-2}{4} = \frac{3}{-k} \\2k=12\\ \boxed{k = 6}$