Math, asked by kitshan78, 17 hours ago

2x-3y=6, x-6y=12 by solving substitution method​

Answers

Answered by jaggs8506
0

Answer:

2x-3y=6 ------ eqn 1

x-6y=12 ------ eqn 2

x= 6y+12 ------ eqn 3

substitute value of x from eqn 3 in eqn 1

2*(6y+12)-3y=6

12y+24-3y=6

9y = -18

y = -2 ------ eqn 4

substitute value of y from eqn 4 in eqn 3

× = 6*(-2) + 12

×=0

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