Question

2x + 3y - 6z = 18
2y - 4/3x + 4z = 12
solve for y.​

Answer 1

SOLUTION

TO DETERMINE

The value of y when

$\sf{2x + 3y - 6z = 18 \: \: \: \: }$

$\displaystyle \sf{ 2y - \frac{4}{3} x + 4z = 12}$

EVALUATION

Here the given two equations are

$\displaystyle \sf{ 2 x + 3y - 6z = 18 \: \: \: - - - - - (1)}$

$\displaystyle \sf{ 2y - \frac{4}{3} x + 4z = 12} \: \: - - - - (2)$

On simplification we get

$\displaystyle \sf{ 6y - 4 x + 12z = 36}$

$\displaystyle \sf{ \implies \: - 4 x + 6y + 12z = 36}$

$\displaystyle \sf{ \implies \: - 2 x + 3y + 6z = 18 \: \: \: - - - - - (3)}$

Equation (1) + Equation (3) gives

$\displaystyle \sf{ \implies \: 6y = 36}$

$\displaystyle \sf{ \implies \: y = 6}$

FINAL ANSWER

Hence the required value of y = 6

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