Math, asked by aniket140804, 11 months ago

2x+3y =7;3x-y =4 by substituting method​

Answers

Answered by aman8431
1

Answer:

Heyy mate ❤✌❤

Here's your Answer...

⤵️⤵️⤵️⤵️⤵️⤵️

✴ 2x + 3y = 7

=> 2x = 7 - 3y

=> x =( 7- 3y)/2 --------(1)

Putting equation 1 in equation 2.

=> 3x - y = 5

=> 3 ×( 7 -3y)/2 -y =5

=> 21/2 - 9/2y - y = 5

=> 21/2 - 5 = 9/2y + y

=> (21 - 10)/2 = (9y + 2y)/2

=> 21 - 10 = 9y + 2y

=> 11 = 11y

=> y = 1.

Putting y=1 in equation 1.

2x + 3y = 7

=> 2x = 7 - 3

=> x = 4/2

=> x = 2.

✔✔✔

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Answered by naina5816
0

Answer:

2x +3y = 7 -----(1)

3x - y = 4 ------(2)

in equ. 1 multiply by 3 & in equation 2 multiply by 2 ---

6x + 9y = 21

6x - 2y = 8

- + -

---------------------

11y = 13

y = 13/11

in equation 1 find the value y = 13/11

2x + 3y = 7

2x + 3×13/11 =7

2x + 39/11 = 7

2x = 7 - 39/11

2x = 38/11

x = 38×2/11

x = 76/11

hope it helps u.

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