2x+3y =7;3x-y =4 by substituting method
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1
Answer:
Heyy mate ❤✌❤
Here's your Answer...
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✴ 2x + 3y = 7
=> 2x = 7 - 3y
=> x =( 7- 3y)/2 --------(1)
Putting equation 1 in equation 2.
=> 3x - y = 5
=> 3 ×( 7 -3y)/2 -y =5
=> 21/2 - 9/2y - y = 5
=> 21/2 - 5 = 9/2y + y
=> (21 - 10)/2 = (9y + 2y)/2
=> 21 - 10 = 9y + 2y
=> 11 = 11y
=> y = 1.
Putting y=1 in equation 1.
2x + 3y = 7
=> 2x = 7 - 3
=> x = 4/2
=> x = 2.
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Answered by
0
Answer:
2x +3y = 7 -----(1)
3x - y = 4 ------(2)
in equ. 1 multiply by 3 & in equation 2 multiply by 2 ---
6x + 9y = 21
6x - 2y = 8
- + -
---------------------
11y = 13
y = 13/11
in equation 1 find the value y = 13/11
2x + 3y = 7
2x + 3×13/11 =7
2x + 39/11 = 7
2x = 7 - 39/11
2x = 38/11
x = 38×2/11
x = 76/11
hope it helps u.
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