Math, asked by Anonymous, 7 months ago

2x+3y=7;3x-y=5 solve by substituting method ​

Answers

Answered by gauravkumar2424
3

Answer:

Heyy mate

Here's your Answer...

⤵️⤵️⤵️⤵️⤵️⤵️

✴ 2x + 3y = 7

=> 2x = 7 - 3y

=> x =( 7- 3y)/2 --------(1)

Putting equation 1 in equation 2.

=> 3x - y = 5

=> 3 ×( 7 -3y)/2 -y =5

=> 21/2 - 9/2y - y = 5

=> 21/2 - 5 = 9/2y + y

=> (21 - 10)/2 = (9y + 2y)/2

=> 21 - 10 = 9y + 2y

=> 11 = 11y

=> y = 1.

Putting y=1 in equation 1.

2x + 3y = 7

=> 2x = 7 - 3

=> x = 4/2

=> x = 2.

✔✔✔

Answered by InfiniteSoul
22

\sf{\underline{\boxed{\large{\blue{\mathsf{Solution}}}}}}

\sf{\bold{\green{\underline{\underline{Given}}}}}

  • Solve by substituting method

_______________________

\sf{\bold{\green{\underline{\underline{To\:Find}}}}}

  • Value of x and y

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\sf{\bold{\green{\underline{\underline{Solution}}}}}

: \sf\implies\:{\bold{ 2x + 3y = 7 }}

⠀⠀⠀⠀

: \sf\implies\:{\bold{ 2x = 7 - 3y}}

⠀⠀⠀⠀

: \sf\implies\:{\bold{ x  = \dfrac{ 7 - 3y}{2} }}----- ( i )

⠀⠀⠀⠀

: \sf\implies\:{\bold{ 3x - y = 5 }}

  • Putting value of x from eq ( i )

⠀⠀⠀⠀

: \sf\implies\:{\bold{ 3 \times \dfrac{ 7 -3y}{ 2} - y = 5 }}

⠀⠀⠀⠀

: \sf\implies\:{\bold{\dfrac{21 - 9y }{2} - y = 5}}

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: \sf\implies\:{\bold{ \dfrac{ 21 - 9y -2y }{ 2} = 5 }}

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: \sf\implies\:{\bold{ 21 - 11y = 10  }}

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: \sf\implies\:{\bold{ 11y = 21 - 10 }}

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: \sf\implies\:{\bold{ 11y = 11 }}

⠀⠀⠀⠀

: \sf\implies\:{\bold{ y = 1 }}

⠀⠀⠀⠀

\sf{\red{\boxed{\bold{y = 1}}}}

⠀⠀⠀⠀

  • Putting value of y in eq ( i )

⠀⠀

: \sf\implies\:{\bold{ 3x - y = 5 }}

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: \sf\implies\:{\bold{ 3x - 1 = 5 }}

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: \sf\implies\:{\bold{ 3x = 5 + 1 }}

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: \sf\implies\:{\bold{ 3x = 6  }}

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: \sf\implies\:{\bold{ x = 2 }}

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\sf{\red{\boxed{\bold{x = 2}}}}

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\sf{\bold{\green{\underline{\underline{Answer}}}}}

  • Value of x = 2 and y = 1
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