Math, asked by sanjana66, 1 year ago

2x-3y=7 5x+y=9 in elimination of substitution method

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Answered by afsanakasmani
27
2x-3y=7______(1)
5x+y=9_______(2)

equation (2) is multiplied by 3
15x+3y=27_______(3)

equations (1) and (3) are added.....
2x-3y=7
15x+3y=27
__________
17x=34
x= 34/17
x= 2

the value of x is kept in equation (1)
2x-3y=7
2(2)-3y=7
4 - 3y=7
-3y=7-4
-3y=3
y=3/-3
y= -1


sanjana66: tq
afsanakasmani: welcome
Answered by gowdayashasgowda
6

Answer:

2x−3y=7 ----------------(1)

5x+y=9

y=9−5x-------------(2)

Now, substitute equation (2) in equation (1)

Then ,2x−3(9−5x)=7

2x−27+15x=7

17x=27+7

17x=34

x=34/17=2

y=9−5×2=9−10=−1

Therefore x is 2 and y is −1

Step-by-step explanation:

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