2x-3y=7 5x+y=9 in elimination of substitution method
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2x-3y=7______(1)
5x+y=9_______(2)
equation (2) is multiplied by 3
15x+3y=27_______(3)
equations (1) and (3) are added.....
2x-3y=7
15x+3y=27
__________
17x=34
x= 34/17
x= 2
the value of x is kept in equation (1)
2x-3y=7
2(2)-3y=7
4 - 3y=7
-3y=7-4
-3y=3
y=3/-3
y= -1
5x+y=9_______(2)
equation (2) is multiplied by 3
15x+3y=27_______(3)
equations (1) and (3) are added.....
2x-3y=7
15x+3y=27
__________
17x=34
x= 34/17
x= 2
the value of x is kept in equation (1)
2x-3y=7
2(2)-3y=7
4 - 3y=7
-3y=7-4
-3y=3
y=3/-3
y= -1
sanjana66:
tq
Answered by
6
Answer:
2x−3y=7 ----------------(1)
5x+y=9
y=9−5x-------------(2)
Now, substitute equation (2) in equation (1)
Then ,2x−3(9−5x)=7
2x−27+15x=7
17x=27+7
17x=34
x=34/17=2
y=9−5×2=9−10=−1
Therefore x is 2 and y is −1
Step-by-step explanation:
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