2x+3y=7;(a-1) x+(a+2) y=3a has infinite solution then find a
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Comparing the above equations with a1x + b1y = c1 and a2x + b2y = c2
a1= 2, b1= 3 and c1= -7
a2= a-1, b2= a+2 and c2= -3a
Since, the given equations has infinite solutions, then
(a1/a2) = (b1/b2) = (c1/c2)
2/a-1= 3/a+2= -7/-3a
2a+4= 3a-3
4+3= 3a-2a
a= 7
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