2x+3y=7 and 5x-2y=8 solve by elimination and substitution method
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Answer:
x=2
y=1
Step-by-step explanation:
by substitution method
2x+3y=7-----(1)
5x-2y=8-----(2)
from eq. (1)
x=7-3y/2------(3)
put the value of x in eq. (2)
5(7-3y/2)-2y=8
35-15y-4y=16
35-19y=16
35-16=19y
y=1
put the value of y in eq. (1)
2x+3y=7
2x+3×1=7
2x+3=7
2x=7-3
2x=4
x=2
by elimination method
multiply by 5 in eq. (1) and multiply by 2 in eq. (2)
then they will be
10x+15y=35
10x-4y=16
---------------
change the sign
so common things will be cancel
then we get
19y=19
y=1
put the value of y in eq.(1)
10x+15=35
10x=20
x=2
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