Question

2x+3y=7 and xy=2 find 8x³+27y³​

Answer 1

Answer:

$2x + 3y = 7$

$xy = 2$

$8x {}^{3} + 27y {}^{3}$

$(2x) {}^{3} + (3y) {}^{3}$

$(2x + 3y) {}^{3} - 3xy(2x + 3y)$

$(7) {}^{3} - 3 \times 2(7)$

$343 - 42$

$301$