2x + 3y = -8
2x + y = -4
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Given Equations are
2x + 3y = -8 ..........(1.)
And
2x + y = -4 ..........(2.)
Solution:-
At first
taking equation (1.)
2x + 3y = -8
=> 2x = - 8 - 3y
Putting the value of 2x in (2.)
we get
2x + y = -4
=> ( -8 - 3y) + y = -4
=> -3y + y = -4 + 8
=> -2y = 4
=> y = -4/2 = -2
Now,
putting y in equation (2.)
we get
2x + y = -4
=> 2x + (-2) = -4
=> 2x - 2 = - 4
=> 2x = -4 + 2 = - 2
=> x = -2/2 = -1
Hence;
x = -1 And y = -2 Answer
# hope it helps :)
Given Equations are
2x + 3y = -8 ..........(1.)
And
2x + y = -4 ..........(2.)
Solution:-
At first
taking equation (1.)
2x + 3y = -8
=> 2x = - 8 - 3y
Putting the value of 2x in (2.)
we get
2x + y = -4
=> ( -8 - 3y) + y = -4
=> -3y + y = -4 + 8
=> -2y = 4
=> y = -4/2 = -2
Now,
putting y in equation (2.)
we get
2x + y = -4
=> 2x + (-2) = -4
=> 2x - 2 = - 4
=> 2x = -4 + 2 = - 2
=> x = -2/2 = -1
Hence;
x = -1 And y = -2 Answer
# hope it helps :)
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