Question

2x+3y=8. 4x+6y=7 substitution method

Answer 1

Answer:

2x+3y=8

2x=8-3y

x=8-3y

2

substituting this value in eq 1 we get

4(8-3y) + 6y =7

2

32-12y + 6y = 7

2

move 2 to RHS

32 -12y + 6y = 14

12y - 6y = 32 -14

6y = 18

y=18

6

y = 3

putting value of y in eq 1 we get

2x + 3(3) = 8

2x+9=8

2x=-1

x= -1

2

Answer 2

$\bold\pink{2x + 3y = 8}$

$\bold\purple{4x + 6y = 7}$

${\fbox{\red{Multiply \: by \: 4}}}$

$\bold\blue{4x + 6y = 16}$

${\fbox{LHS \: of \: i \: and \: ii \: are \: same \: but \: RHS\: is \: different}}$

${\fbox{\color{lime}{Hence \: the \: solution \: does \: not \: exist}}}$......