Question

2x+3y=8&4x+6y=7 by substitution method

Answer 1

Soln,
2x+3y=8
or, 2x=8-3y
or, x=(8-3y)/2.....(i)
And,
4x+6y=7
or, 6y=7-4x......(ii)
Substituting eqn(i) in Eqn(ii),
6y = 7 - 4*{(8-3y)/2}
or, 6y=7-2*(8-3y)
or, 6y=7-16+6y
or, 6y - 6y = -9
or, 0 = -9 (which is false)
So this question cannot be solved I guess.

Answer 2

Step-by-step explanation:

$\bold\pink{2x + 3y = 8}$

$\bold\purple{4x + 6y = 7}$

${\fbox{\red{Multiply \: by \: 4}}}$

$\bold\blue{4x + 6y = 16}$

${\fbox{LHS \: of \: i \: and \: ii \: are \: same \: but \: RHS\: is \: different}}$

${\fbox{\color{yellow}{Hence \: the \: solution \: does \: not \: exist}}}$