Question

2x - 3y = 8 and 4x + 6y = 10 substitutional method​

Answer 1

Answer:

$2x - 3y = 8 \\ \\ 2x = 8 + 3y \\ \\ x = \frac{8 + 3y}{2} \\ \\ 4x + 6y = 10 \\ \\ 4( \frac{8 + 3y}{2} ) + 6y = 10 \\ \\ 2(8 + 3y) + 6y = 10 \\ \\ 16 + 6y + 6y = 10 \\ \\ 16 + 12y = 10 \\ \\ 12y = 10 - 16 \\ \\ 12y = - 6 \\ \\ y = - \frac{1}{2} \\ \\ \\ \\ x = \frac{8 + 3y}{2} \\ \\ x = \frac{8 +3( \frac{ - 1}{2}) }{2} \\ \\ x = \frac{8 + (\frac{ - 3}{2}) }{2} \\ \\ x = \frac{8 - 1.5}{2} \\ \\ x = \frac{ - 6.5}{2} \\ \\ x = - 3.25$

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Answer 2

Answer:

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Step-by-step explanation:

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