Question

2x+ 3y=8 and x-2y+3=0 by elimination method​

Answer 1

Answer:

Hii,

Step-by-step explanation:

$\huge\underline{\underline{\boxed{\mathcal\blue{Answer:-}}}}$

$\sf\bold{\underline{Given:-}}$

::::---- 2x + 3y = 8. (1) ::::---- x - 2y + 3 = 0. (2)

In equation (2),

:::::----- x = -3 + 2y. (3)

$\small\underline{\underline{\boxed{\mathcal\pink{Solution:-}}}}$

$Substitute \: the \: value \: of \: x \: in \: eq. \: (1),$

2(-3 + 2y) + 3y = 8

-6 + 4y + 3y = 8

7y = 8 + 6

7y = 14

y = 14/7

y = 2

$\small\underline{\underline{\boxed{\boxed{\mathcal\pink{From \: equation \: 3}}}}}$

x = -3 + 2y

x = -3 + 2(2) { Putting the value of y, where y = 2 }

x = -3 + 4

x = 1

$\sf\bold{\underline{Check:-}}$

2(1) + 3(2) = 2 + 6 = 8. (1)

1 - 2(2) + 3 = 1 - 4 + 3 = 0. (2)

$\small\underline{\underline{\boxed{\mathcal\red{HOPE \: IT \: WILL \: HELP \: YOU}}}}$

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