2x+3y-9=0 and 4x+6y-18=0 algebraically
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Answered by
1
Answer:
2x+3y-9=0
2x+3y=0+9
2x+3y=9
4x+6y-18=0
4x+6y=0+18
Answered by
10
Given:-
2x+3y=9 ..(1)
4x+6y=18 ..(2)
From equation (1)
x=\frac{9-3y}{2}29−3y ..(3)
Substituting equation (3) in equation (2)
4\frac{(9-3y)}{2}2(9−3y) +6y=18
2(9-3y)+6y=18
18-6y+6y=18
18=18
The given equation will have infinitely many solutions.
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