Math, asked by ashraf55, 1 year ago

2x - 3y = 9; 2x + y = 13 solving linear equations in two variables with full process of solving ​

Answers

Answered by sarojjha742
2

Step-by-step explanation:

first 2x-3y=9

(1)X=0, Y=-3

2×0-3×{-3}

-3×-3

9

(2) X=4,Y=1

2×4-3×1

12-3

9

second 2x+y=13

(1)X=5,Y=3

2×5+3

10+3

13

(2) X=7,Y=-1

2×7+(-1)

14-1

13

Answered by shivasidar9756
1

Answer:

First of all you have to compare both the equation by subtracting the smaller eq from the larger eq.

Step-by-step explanation:

Here, take 2x-3y = 9 as Eq no (1) and the another one as eq no (2)

Now subtract eq 1 from 2

2x+y-(2x-3y) = 13 - 9

2x + y -2x + 3y = 4  (Here 2x - 2x = 0  I am not writing in the next line)

4y = 4

y = 4/4

y = 1   (Put the  value of y in any of the equation and you will get the value of x)

2x - y = 9

2x - 1 = 9

2x = 10

x = 10/2

x =5

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