Question

2x - 3y = 9; 2x + y = 13 that is so simple now sol it​

Answer 1

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Answer 2

$\large\underline{\sf{Solution-}}$

Given pair of linear equations are

$\rm :\longmapsto\:2x - 3y = 9 - - - (1)$

and

$\rm :\longmapsto\:2x + y = 13 - - - (2)$

From equation (2), we have

$\rm :\longmapsto\:2x = 13 - y - - - - (3)$

Substituting the value of 2x in equation (1), we get

$\rm :\longmapsto\:13 - y - 3y = 9$

$\rm :\longmapsto\:13 -4y = 9$

$\rm :\longmapsto\: -4y = 9 - 13$

$\rm :\longmapsto\: -4y = - 4$

$\bf\implies \:y = 1$

On substituting y = 1, in equation (3), we get

$\rm :\longmapsto\:2x = 13 - 1$

$\rm :\longmapsto\:2x = 12$

$\bf\implies \:x = 6$

So,

$\begin{gathered}\begin{gathered}\rm :\longmapsto\:\bf\: Solution-\begin{cases} &\sf{x = 6} \\ &\sf{y = 1} \end{cases}\end{gathered}\end{gathered}$

Alternative Method :-

Given pair of linear equations are

$\rm :\longmapsto\:2x - 3y = 9 - - - (1)$

and

$\rm :\longmapsto\:2x + y = 13 - - - (2)$

On Subtracting equation (2) from equation (1), we get

$\rm :\longmapsto\: - 4y = - 4$

$\bf\implies \:y = 1$

On substituting y = 1 in equation (2), we get

$\rm :\longmapsto\:2x + 1 = 13$

$\rm :\longmapsto\:2x = 13 - 1$

$\rm :\longmapsto\:2x = 12$

$\bf\implies \:x = 6$

So,

$\begin{gathered}\begin{gathered}\rm :\longmapsto\:\bf\: Solution-\begin{cases} &\sf{x = 6} \\ &\sf{y = 1} \end{cases}\end{gathered}\end{gathered}$